Optimal. Leaf size=216 \[ \frac{d^2 e^4 (52 d+25 e x) \sqrt{d^2-e^2 x^2}}{8 x}+\frac{d e^3 (25 d-52 e x) \left (d^2-e^2 x^2\right )^{3/2}}{24 x^2}-\frac{e^2 (52 d+25 e x) \left (d^2-e^2 x^2\right )^{5/2}}{60 x^3}-\frac{3 e \left (d^2-e^2 x^2\right )^{7/2}}{4 x^4}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{5 x^5}+\frac{13}{2} d^3 e^5 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{25}{8} d^3 e^5 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right ) \]
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Rubi [A] time = 0.313177, antiderivative size = 216, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 8, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.296, Rules used = {1807, 813, 844, 217, 203, 266, 63, 208} \[ \frac{d^2 e^4 (52 d+25 e x) \sqrt{d^2-e^2 x^2}}{8 x}+\frac{d e^3 (25 d-52 e x) \left (d^2-e^2 x^2\right )^{3/2}}{24 x^2}-\frac{e^2 (52 d+25 e x) \left (d^2-e^2 x^2\right )^{5/2}}{60 x^3}-\frac{3 e \left (d^2-e^2 x^2\right )^{7/2}}{4 x^4}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{5 x^5}+\frac{13}{2} d^3 e^5 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{25}{8} d^3 e^5 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right ) \]
Antiderivative was successfully verified.
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Rule 1807
Rule 813
Rule 844
Rule 217
Rule 203
Rule 266
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(d+e x)^3 \left (d^2-e^2 x^2\right )^{5/2}}{x^6} \, dx &=-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{5 x^5}-\frac{\int \frac{\left (d^2-e^2 x^2\right )^{5/2} \left (-15 d^4 e-13 d^3 e^2 x-5 d^2 e^3 x^2\right )}{x^5} \, dx}{5 d^2}\\ &=-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{5 x^5}-\frac{3 e \left (d^2-e^2 x^2\right )^{7/2}}{4 x^4}+\frac{\int \frac{\left (52 d^5 e^2-25 d^4 e^3 x\right ) \left (d^2-e^2 x^2\right )^{5/2}}{x^4} \, dx}{20 d^4}\\ &=-\frac{e^2 (52 d+25 e x) \left (d^2-e^2 x^2\right )^{5/2}}{60 x^3}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{5 x^5}-\frac{3 e \left (d^2-e^2 x^2\right )^{7/2}}{4 x^4}-\frac{\int \frac{\left (150 d^6 e^3+312 d^5 e^4 x\right ) \left (d^2-e^2 x^2\right )^{3/2}}{x^3} \, dx}{72 d^4}\\ &=\frac{d e^3 (25 d-52 e x) \left (d^2-e^2 x^2\right )^{3/2}}{24 x^2}-\frac{e^2 (52 d+25 e x) \left (d^2-e^2 x^2\right )^{5/2}}{60 x^3}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{5 x^5}-\frac{3 e \left (d^2-e^2 x^2\right )^{7/2}}{4 x^4}+\frac{\int \frac{\left (-1248 d^7 e^4+600 d^6 e^5 x\right ) \sqrt{d^2-e^2 x^2}}{x^2} \, dx}{192 d^4}\\ &=\frac{d^2 e^4 (52 d+25 e x) \sqrt{d^2-e^2 x^2}}{8 x}+\frac{d e^3 (25 d-52 e x) \left (d^2-e^2 x^2\right )^{3/2}}{24 x^2}-\frac{e^2 (52 d+25 e x) \left (d^2-e^2 x^2\right )^{5/2}}{60 x^3}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{5 x^5}-\frac{3 e \left (d^2-e^2 x^2\right )^{7/2}}{4 x^4}-\frac{\int \frac{-1200 d^8 e^5-2496 d^7 e^6 x}{x \sqrt{d^2-e^2 x^2}} \, dx}{384 d^4}\\ &=\frac{d^2 e^4 (52 d+25 e x) \sqrt{d^2-e^2 x^2}}{8 x}+\frac{d e^3 (25 d-52 e x) \left (d^2-e^2 x^2\right )^{3/2}}{24 x^2}-\frac{e^2 (52 d+25 e x) \left (d^2-e^2 x^2\right )^{5/2}}{60 x^3}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{5 x^5}-\frac{3 e \left (d^2-e^2 x^2\right )^{7/2}}{4 x^4}+\frac{1}{8} \left (25 d^4 e^5\right ) \int \frac{1}{x \sqrt{d^2-e^2 x^2}} \, dx+\frac{1}{2} \left (13 d^3 e^6\right ) \int \frac{1}{\sqrt{d^2-e^2 x^2}} \, dx\\ &=\frac{d^2 e^4 (52 d+25 e x) \sqrt{d^2-e^2 x^2}}{8 x}+\frac{d e^3 (25 d-52 e x) \left (d^2-e^2 x^2\right )^{3/2}}{24 x^2}-\frac{e^2 (52 d+25 e x) \left (d^2-e^2 x^2\right )^{5/2}}{60 x^3}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{5 x^5}-\frac{3 e \left (d^2-e^2 x^2\right )^{7/2}}{4 x^4}+\frac{1}{16} \left (25 d^4 e^5\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{d^2-e^2 x}} \, dx,x,x^2\right )+\frac{1}{2} \left (13 d^3 e^6\right ) \operatorname{Subst}\left (\int \frac{1}{1+e^2 x^2} \, dx,x,\frac{x}{\sqrt{d^2-e^2 x^2}}\right )\\ &=\frac{d^2 e^4 (52 d+25 e x) \sqrt{d^2-e^2 x^2}}{8 x}+\frac{d e^3 (25 d-52 e x) \left (d^2-e^2 x^2\right )^{3/2}}{24 x^2}-\frac{e^2 (52 d+25 e x) \left (d^2-e^2 x^2\right )^{5/2}}{60 x^3}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{5 x^5}-\frac{3 e \left (d^2-e^2 x^2\right )^{7/2}}{4 x^4}+\frac{13}{2} d^3 e^5 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{1}{8} \left (25 d^4 e^3\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{d^2}{e^2}-\frac{x^2}{e^2}} \, dx,x,\sqrt{d^2-e^2 x^2}\right )\\ &=\frac{d^2 e^4 (52 d+25 e x) \sqrt{d^2-e^2 x^2}}{8 x}+\frac{d e^3 (25 d-52 e x) \left (d^2-e^2 x^2\right )^{3/2}}{24 x^2}-\frac{e^2 (52 d+25 e x) \left (d^2-e^2 x^2\right )^{5/2}}{60 x^3}-\frac{d \left (d^2-e^2 x^2\right )^{7/2}}{5 x^5}-\frac{3 e \left (d^2-e^2 x^2\right )^{7/2}}{4 x^4}+\frac{13}{2} d^3 e^5 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{25}{8} d^3 e^5 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )\\ \end{align*}
Mathematica [C] time = 0.104517, size = 199, normalized size = 0.92 \[ \frac{\sqrt{d^2-e^2 x^2} \left (-\frac{7 d^{11} \, _2F_1\left (-\frac{5}{2},-\frac{5}{2};-\frac{3}{2};\frac{e^2 x^2}{d^2}\right )}{x^5 \sqrt{1-\frac{e^2 x^2}{d^2}}}-\frac{35 d^9 e^2 \, _2F_1\left (-\frac{5}{2},-\frac{3}{2};-\frac{1}{2};\frac{e^2 x^2}{d^2}\right )}{x^3 \sqrt{1-\frac{e^2 x^2}{d^2}}}+5 e^5 \left (e^2 x^2-d^2\right )^3 \, _2F_1\left (2,\frac{7}{2};\frac{9}{2};1-\frac{e^2 x^2}{d^2}\right )+15 e^5 \left (e^2 x^2-d^2\right )^3 \, _2F_1\left (3,\frac{7}{2};\frac{9}{2};1-\frac{e^2 x^2}{d^2}\right )\right )}{35 d^4} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.086, size = 327, normalized size = 1.5 \begin{align*} -{\frac{13\,{e}^{2}}{15\,d{x}^{3}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}+{\frac{52\,{e}^{4}}{15\,{d}^{3}x} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}+{\frac{52\,{e}^{6}x}{15\,{d}^{3}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}+{\frac{13\,{e}^{6}x}{3\,d} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}}+{\frac{13\,d{e}^{6}x}{2}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}+{\frac{13\,{d}^{3}{e}^{6}}{2}\arctan \left ({x\sqrt{{e}^{2}}{\frac{1}{\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}}} \right ){\frac{1}{\sqrt{{e}^{2}}}}}-{\frac{d}{5\,{x}^{5}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}-{\frac{3\,e}{4\,{x}^{4}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}+{\frac{5\,{e}^{3}}{8\,{d}^{2}{x}^{2}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}+{\frac{5\,{e}^{5}}{8\,{d}^{2}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}+{\frac{25\,{e}^{5}}{24} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}}+{\frac{25\,{d}^{2}{e}^{5}}{8}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}-{\frac{25\,{d}^{4}{e}^{5}}{8}\ln \left ({\frac{1}{x} \left ( 2\,{d}^{2}+2\,\sqrt{{d}^{2}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}} \right ) } \right ){\frac{1}{\sqrt{{d}^{2}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.90585, size = 387, normalized size = 1.79 \begin{align*} -\frac{1560 \, d^{3} e^{5} x^{5} \arctan \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{e x}\right ) - 375 \, d^{3} e^{5} x^{5} \log \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{x}\right ) - 80 \, d^{3} e^{5} x^{5} -{\left (40 \, e^{7} x^{7} + 180 \, d e^{6} x^{6} + 80 \, d^{2} e^{5} x^{5} + 656 \, d^{3} e^{4} x^{4} + 345 \, d^{4} e^{3} x^{3} - 32 \, d^{5} e^{2} x^{2} - 90 \, d^{6} e x - 24 \, d^{7}\right )} \sqrt{-e^{2} x^{2} + d^{2}}}{120 \, x^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 17.522, size = 1197, normalized size = 5.54 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.25596, size = 581, normalized size = 2.69 \begin{align*} \frac{13}{2} \, d^{3} \arcsin \left (\frac{x e}{d}\right ) e^{5} \mathrm{sgn}\left (d\right ) - \frac{25}{8} \, d^{3} e^{5} \log \left (\frac{{\left | -2 \, d e - 2 \, \sqrt{-x^{2} e^{2} + d^{2}} e \right |} e^{\left (-2\right )}}{2 \,{\left | x \right |}}\right ) + \frac{{\left (6 \, d^{3} e^{12} + \frac{45 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )} d^{3} e^{10}}{x} + \frac{50 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{2} d^{3} e^{8}}{x^{2}} - \frac{600 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{3} d^{3} e^{6}}{x^{3}} - \frac{2580 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{4} d^{3} e^{4}}{x^{4}}\right )} x^{5} e^{3}}{960 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{5}} + \frac{1}{960} \,{\left (\frac{2580 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )} d^{3} e^{38}}{x} + \frac{600 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{2} d^{3} e^{36}}{x^{2}} - \frac{50 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{3} d^{3} e^{34}}{x^{3}} - \frac{45 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{4} d^{3} e^{32}}{x^{4}} - \frac{6 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{5} d^{3} e^{30}}{x^{5}}\right )} e^{\left (-35\right )} + \frac{1}{6} \,{\left (4 \, d^{2} e^{5} +{\left (2 \, x e^{7} + 9 \, d e^{6}\right )} x\right )} \sqrt{-x^{2} e^{2} + d^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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